If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+10x-160=0
a = 4; b = 10; c = -160;
Δ = b2-4ac
Δ = 102-4·4·(-160)
Δ = 2660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2660}=\sqrt{4*665}=\sqrt{4}*\sqrt{665}=2\sqrt{665}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{665}}{2*4}=\frac{-10-2\sqrt{665}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{665}}{2*4}=\frac{-10+2\sqrt{665}}{8} $
| 3x-2=3x+9 | | (x+2/x)=4 | | (2t-7)(5t+6)=0 | | 1/3(24p-66)=3p+40 | | x^2-16x+47=-16 | | U/4=u/5+3 | | 3x+4/2=24 | | y+43=65 | | (t-8)(t-9)=0 | | y-22=66 | | 9w+5=4.7w-7.6 | | (x+1/x+3)=2 | | x+4=6×-1 | | -j-(-17)=36 | | 6s-s-(4)+5-2s=18 | | 5=4x/6 | | 4y^2+28y-1=7 | | 3x-4=2x+-5X | | w=1/10=1/5 | | 3x-4=2x+-5 | | 1/3x+2/3=0.6 | | X^+3x-108=0 | | √(x^2+1)+x=0 | | (5x-3)²=(4x-7)² | | X^+16x+60=0 | | 9(x+4)=3(3x+2)=30 | | 2/5=r | | 48=-6+2x | | 12=2k+7-1 | | 3d^2-75=0 | | 4x=-109+5(5x+5) | | 30=-5/6x |